1.(1)mO2=1000-920=80g

2H2O2→2H2O+O2↑

mH2O2(分解)=170g

(2)mH202(剩余)=1000×30%-170=130g

c%=[130÷(1000-80)]×100%≈14.13%

2.mO2=0.224×1.43≈0.32g

n02=0.01mol

2CaO2+2H20→2Ca(OH)2+O2↑

nCaO2=0.02mol

mCaO2=1.44g

cCaO2%=(1.44÷2)×100%=72%